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Power Girl, ‘Wonder Woman’ Vol 3 #41

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ByPatrick Ouandji
 
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Helping you become your own version of a Superhero in your life (IRL)

-Superhero Therapy

IN POWER GIRL VS WONDER WOMAN

 

POWER GIRL (KAREN STARR)
EARTH-TWO

In Wonder Woman (2010) #41 titled “A Murder Of Crows, Part Two”, Power Girl performs a super-strength feat. Wonder Woman fights Power Girl possessed by the Children of Ares. During the fight, Power Girl punches Wonder Woman to Canada.

How much super-strength does it take to punch Wonder Woman to Canada?

  • In Wonder Woman (2010) #41, Power Girl possessed by the Children of Ares performs a super-strength feat. Power Girl punches Wonder Woman to Canada. DC Comics.

 
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VOTED FOR DC UNIVERSE OR MARVEL ENTERTAINMENT? JOIN OUR LEAGUE OF HEROES AND READ A KEY ISSUE

IN THE ISSUE, POWER GIRL PUNCHED WONDER WOMAN IN A PERFECTLY ELASTIC COLLISION OVER 2,877,507 METERS.

IMPORTANTLY, THE PUNCH GENERATED A TOTAL WORK OF 1.6185977*1019 JOULES. SIMILARLY, THE EQUIVALENT OF 3.76418069767 PERCENT OF THE ENERGY RECEIVED BY THE EARTH FROM THE SUN. ENOUGH TO DESTROY A LARGE ISLAND.

SUPER-STRENGTH FEAT:

PLANETARY

Super Strength: Planetary 50%

For our database entries on DC Power Levels, visit the DC Characters page!

For the Power Level Scale, visit the Power Level Wiki.

VISIT OUR CALCULATIONS!

Power Girl punched Wonder Woman across the Canadian border. We will use Wonder Woman’s durability in order to estimate the super strength.

WONDER WOMAN’S DURABILITY

In Wonder Woman (2005) #219, Wonder Woman fights a mind-controlled Superman. Bloodlusted, Superman believes he is fighting Doomsday and seeks to kill her. In a powerful blow in space, Superman punches Wonder Woman from the sun to Earth. Fortunately, Diana survives re-entry on Earth.

In Wonder Woman (2005) #219, Wonder Woman survives re-entry on Earth. DC Comics.

We will use this feat to calculate Wonder Woman’s durability.

NUMBER CRUNCHING

In order to estimate Wonder Woman’s durability we need to calculate the power of Superman’s space punch. In space to Earth, there are four powers on Wonder Woman: Hsun or the radiation of the sun on Wonder Woman, Usun or the sun’s gravitational energy, UEarth or the gravitational energy in high orbit and the KE or the kinetic energy from the punch.

Total Work = 1/2mv^2 + mgh + Usun + Hsun = (0.5*75 kg)(150*10^9 m/s)2 + (75 kg * 35786000 m * 4 * 9.81 m/s2) + (3.02085*1012 J) + (1.83 m2 * 1429959739.00 W/(m2*s)) = 8.4375e+23 J.

Then, we estimate the impact force of Superman’s punch.

Force = Total Work/Sun-Earth Distance = (8.4375e+23 J)/(150*10^9 m) = 5.625e+12 N.

Finally, we calculate the work done by Power Girl’s punch over 2877507 m over the Canadian border.

Work = (5.625*1012 N)(2877507 m) = 1.6185977e+19 J = 1.6185977e+19 W.

SUPER STRENGTH

Power Girl generated 1.6185977e+19 J of work with her inter-continental punch. In order to knock out Wonder Woman, Power Girl had to generate a Planetary-Level of Super Strength.

 
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SUPERHERO THERAPY PRACTITIONER? VISIT SUPERHERO DAY

LINKS

Diana of Themyscira (New Earth) in DC Database.
Kara Zor-L (Earth-Two) in DC Database.
Destructive Capacity and Durability in Power Crunch Archive Wiki.
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