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Superman, ‘Superman’ Vol 2 #207

Posted
Updated
ByPatrick Ouandji
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IN REDEMPTION

Superman in the Middle East hovering over the land to stop a war.

SUPERMAN (CLARK KENT)
NEW EARTH

In ‘Superman’ (2004) #207, titled “For Tomorrow, Part Four”, Superman performs a super speed feat. In the Middle East, investigating the Vanishing, Superman fights a mercenary called Equus. During the fight, Superman speedblitzes Equus.

How much super speed does it take for Superman to speedblitz Equus?

In ‘Superman’ (2004) #207, Superman performs a super speed feat. During the fight, Superman speedblitzes Equus. AP Photo/DC Comics
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VOTED FOR DC UNIVERSE OR MARVEL ENTERTAINMENT? JOIN OUR LEAGUE OF HEROES AND READ A KEY ISSUE

IN THE ISSUE, SUPERMAN SPEEDBLITZED EQUUS WITH FIVE PUNCHES DAMAGING HIS CYBERNETIC GOGGLES WITH SHEAR STRENGTH OF 410000 NEWTONS PER METER SQUARED.

IMPORTANTLY, SUPERMAN GENERATED THE EQUIVALENT OF 6,525,352.66677 NEWTONS OF FORCE TO DAMAGE EQUUS’ CYBERNETIC GOGGLES. SIMILARLY, A SPEED BLITZ AT 382.574241775 METERS PER SECOND, 112.521835816 PERCENT OF THE SPEED OF SOUND.

SUPER SPEED FEAT:

SUPERSONIC

Super Speed: Supersonic 58%
The Mightiest Punch!: Is this feat humanly possible?

For more information on the Stress Calculator, visit the Omni-Calculator.

For our database entries of DC Power Levels, visit the DC Characters page!

Head over to ‘How Powerful is the Post Crisis Superman?’ by Comic Books vs The World.

Comic Books vs The World

Superman speedblitzed Equus at tremendous speeds. We will calculate the force of Superman’s five punches to estimate the super speed.

NUMBER CRUNCHING

First, Superman states Equus is as tough as three-grade soft plastic. For our purposes, these are Polypropylene (0.25 MPa), High-Density Polypropylene (0.08 MPa) and Low-Density Polypropylene (0.08 MPa).

When we add up their shear strength, we get 0.41 MPa = 410000 N/m2 = Equus’ durability.

Since Superman likely speedblitzed Equus at supersonic speeds or higher, he punched him 5 times in a short time.

Therefore Superman’s shear stress = F/A = (410000 N/m2 * 2.5 m * 1 m * 5)/(pi * 0.50 m * 0.50 m) = 6525352.66677 N/m2 = 6525352.66677 N.

Now, let’s find the acceleration using the Fourth Kinematics equation.

a = (v12 – v02) / (2 s).

We know F = ma, so a = F/m.

The equation to calculate the final velocity is:

a = (v12 – v02) / (2 s) = F/m.

v1 = (2Fs/m)^(1/2) = ((2*6525352.66677 N*1.2 m)/(107 kg))^(1/2) = 382.574241775 m/s.

For the issue, click on the Amazon product image below to purchase the Kindle & Comixology comic.

*Check Superman #207 (2004) on Price Charting for Buy/Sell.

SOURCES

Superman Vol 2 207 in DC Database.
Equus (New Earth) in DC Database.
User Interface\Analysis Setup\Prepare Analysis\Material Wizard\General Value of Polymer Properties\Shear Stress and Shear Rate Information.htm in Moldex3D.
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