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Aquaman, ‘JLA’ Vol 1 118

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Updated
ByPatrick Ouandji
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*For a better user experience with Comic-Con Trends and the #BestDCComicsArtists, this article uses an AI-enhanced smart links technology.

IN SPORTSMAG

AQUAMAN (ARTHUR CURRY)
NEW EARTH

In JLA (2006) #118, titled “Crisis of Conscience: Part Four”, Aquaman performs a super strength feat. Despero has restored the Secret Society of Super Villains’ memory of the Justice League of America’s secret identities. With the Justice League of America occupied, Aquaman and Martian Manhunter take on Despero. During the fight, Aquaman punches Despero out of San Diego Bay.

How much super strength does it take for Aquaman to punch Despero out of San Diego Bay?

  • In ‘JLA’ (2006) #118, Aquaman punches Despero out of San Diego Bay. DC Comics.

IN THE ISSUE, AQUAMAN PUNCHED DESPERO ONE MILE ABOVE SAN DIEGO BAY. A WORLD RECORD BEYOND 7 CLASSES FOR THE 325-POUND ABDOMINALS AND THIGHS.

RELEVANTLY, FISH ARE KNOWN TO JUMP OUT OF WATER AND DESPERO HAD TO RECEIVE ENOUGH THRUST TO JUMP OUT.

IMPORTANTLY, AQUAMAN GENERATED 7.9008737e+13 NEWTONS OF THRUST. SIMILARLY, THE ABSOLUTE VALUE OF THE POWER OF AQUAMAN’S PUNCH WAS 2.8017622*1016 WATTS. ENOUGH TO DESTROY A CITY.

SUPER-STRENGTH FEAT:

MULTI-CONTINENT

Super-Strength: Multi-Continent 42%

For our database entries on DC Power Levels, visit the DC Characters page!

For the Power Level Scale, visit the Power Level Wiki.

Aquaman punched Despero out of San Diego Bay. We will calculate the thrust required for Despero to jump out of water in order to estimate Aquaman’s super strength.

NUMBER CRUNCHING

At 18 meters deep, the pressure on Despero is 1823850 Newtons. When we calculate the thrust, we find the force necessary to move 2440.5 m3 of volume of water across 1627 meters, that is, 1 mile high from 18 meters of seawater depth.

Though the punch is a collision, we will use Despero jumping out of water like a fish, since the punch sent him a mile above San Diego Bay.

From The Royal Society, we find their study on fish jumping out of water. First, we calculate the maximum velocity U0.

U0 = ((H)(2g))^(1/2) = ((18 m + 1609 m)(2 * 9.81 m/s^2))^(1/2) = 178.666560945 m/s.
Fout ≈ mb(z/L)g = (386 kg*9.81 m/s)((18 m + 1609 m)/(2.46888 m)) = 2495421.33275 N.
Ff=mf(z)g+(d/dt)(mfz˙) = -(48855567275 kg)(9.81 m/s^2) + (48855567275 kg)(1609 m +18 m)/(1 s) = 7.9008735e+13 N.
mbz¨=−Fout−Ff = -2495421.33275 N – 7.9008735e+13 N = -7.9008737e+13 N.

Finally, we calculate the power of the punch.
P = FU0 = (-7.9008737e+13 N * 354.614228141 m/s) = -2.8017622e+16 W.

SUPER-STRENGTH

Aquaman generated at least 7.9008737e+13 N of thrust to punch Despero out of San Diego Bay. Aquaman had to generate a Multi-Continent-Level of Super-Strength.
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SUPERHERO THERAPY PRACTITIONER? VISIT SUPERHERO DAY

LINKS

JLA Vol 1 118 in DC Database.
Jumping dynamics of aquatic animals in The Royal Society.
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