Flash, Wally West, ‘The Flash: Rebirth’ Vol 1 5

 
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IN POWER LEVEL

 

FLASH (WALLY WEST)
NEW EARTH

In The Flash: Rebirth (2010) #5, titled “Mother, May I”, Flash performs a durability feat. In Central City, Professor Zoom has returned from the past to kill the Flash family. During the battle, Wally survives being hit into a bus by Professor Zoom.

How much durability does it take for Flash to survive being hit into a bus?

IN THE ISSUE, FLASH SURVIVED A 10-METER CRASH THROUGH A BUS AFTER PROFESSOR ZOOM HIT HIM WITH A BAT AT MACH TWO.

RELEVANTLY, THE SHEAR STRESS EQUALED THE PRESSURE INSIDE A BUS TIRE.

IMPORTANTLY, FLASH WITHSTOOD 525948 PASCALS OF STRESS. ENOUGH TO DESTROY A BUS TIRE.

DURABILITY FEAT:

METAHUMAN

Durability: Metahuman 17%

For more information about the Stress Calculator, visit the Omni-Calculator.

For our database entries of DC Power Levels, visit the DC Characters page!

Zoom hit Wally into a bus with a baseball bat. We will calculate the strain on the bus in order to estimate Wally’s durability.

NUMBER CRUNCHING


In the issue, Professor Zoom hits Wally West with a baseball bat 10 meters into a bus. Let’s differentiate the acceleration of Zoom’s hit.

a = d/dt(10/dt) = -10/dt2 . dt2 = -10/a.

If we assume that Wally and Zoom were fighting at sonic speed, then his velocity was 343 meters per second. Then, we can calculate the time it takes to accelerate Flash to Mach 2 with the bat. And we square it.

dt2 = (ds/dv)2 = -10/a = -10dt/dv. dt = | -10/dv | = (10 m)/(686 m/s) = 0.01457725947 s.

a = |-10 m/(0.01457725947 s*0.01457725947 s)| = 47059.6000337 m/s2.

F = ma = (47059.6000337 m/s2*79 kg) = 3717708.40266 N.

Finally, we can calculate the shear stress with the Omni-Calculator.

Wally West, ‘Flash: Rebirth’ #5. Omni-Calculator

ENERGY PROJECTION


Professor Zoom hit Flash with a baseball bat 10 meters away into a bus. In order to survive the collision, Flash had to generate a Metahuman-Level of Super Strength.
 
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LINKS

The Flash: Rebirth Vol 1 5 in DC Database.
Stress Calculator in Omni-Calculator.

Flash, Wally West, ‘The Flash’ Vol 2 148

 
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IN POWER LEVEL

 

FLASH (WALLY WEST)
NEW EARTH

In The Flash (1999) #148, titled “Chain Lightning, Chapter Four: Undertow”, Flash performs a super-strength feat. President Malcolm Thawne, Barry Allen‘s twin brother threatens the Speed Force and all the iterations of the Flashes in the timestream with the Blue Gem. During the battle, Flash uses the Infinite Mass Punch to stop Professor Zoom from stealing the Blue Gem.

How much super-strength does it take for Flash to stop Professor Zoom with the Infinite Mass Punch?

  • In 'The Flash' (1999) #148, Flash uses the Infinite Mass Punch to stop Professor Zoom. DC Comics.

IN THE ISSUE, FLASH PUNCHED PROFESSOR ZOOM WITH THE MASS OF A WHITE DWARF STAR AT LIGHTSPEED.

RELEVANTLY, WHITE DWARF STARS CAN REACH A THIRD OF THE SPEED OF LIGHT.

IMPORTANTLY, THE INFINITE MASS PUNCH GENERATED 1.7901*1047 JOULES OF KINETIC ENERGY. SIMILARLY, THE EQUIVALENT OF 2.72727272727 TIMES THE KINETIC ENERGY OF THE MILKY WAY GALAXY. ENOUGH TO DESTROY A LARGE STAR.

SUPER-STRENGTH FEAT:

GALAXY

Super Strength: Galaxy 75%

For our database entries of DC Power Levels, visit the DC Characters page!

In order to defeat Zoom, Flash performs the Infinite Mass Punch. We will calculate the kinetic energy of a white dwarf star to estimate Flash’s super-strength.

NUMBER CRUNCHING

In the issue, Wally West states that at lightspeed, his punch hits with the mass of a white dwarf star. We will calculate the kinetic energy of a white dwarf star at lightspeed. A propos, stars in space travel at a third of the speed of light. We will assume one solar mass.

KE = E = mc2 = (0.5)(1.989 × 10^30 kg)(3*10^8 m/s)2 = 1.7901e+47 J.

ENERGY PROJECTION

Accelerating his mass to the mass of a white dwarf star, Wally hit Professor Zoom with the Infinite Mass Punch.
Though Flash generated infinite momentum. In order to knock out Zoom, Flash had to generate a Galaxy-Level of Super Strength.

 
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LINKS

The Flash Vol 2 148 in DC Database.
On the Total Kinetic Energy of Our Galaxy with the Contribution of the Populations in Springer Link.

Superman, ‘Action Comics’ Vol 1 847

 
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IN POWER LEVEL

Superman in the Middle East hovering over the land to stop a war.

SUPERMAN (CLARK KENT)
NEW EARTH

In Action Comics (2007) #847, titled “Intermezzo”, Superman performs a durability feat. In space with Pa Kent, Superman delivers an entropy bomb to a Sun-Eater. During the fight, a Superman weakned by red sun radiation withstands an explosion equal to 50 Kepler supernovae.

How much durability does it take for Superman to withstand an explosion equal to 50 Kepler supernovae?

*Visit Lex Luthor, Action Comics Annual Vol 1 #11 for our calculations.

IN THE ISSUE, SUPERMAN WEAKENED BY RED SUN RADIATION WITHSTOOD AN EXPLOSION 50 TIMES THE SIZE OF THE KEPLER SUPERNOVA.

RELEVANTLY, THE KEPLER SUPERNOVA HAS A DISTANCE OF 10000 LIGHTYEARS OR 9.4607*1019 METERS.

IMPORTANTLY, SUPERMAN GENERATED A TOTAL WORK OF 6.3*1046 JOULES. SIMILARLY, THE EQUIVALENT OF 1.3318253*1025 NEWTONS OF CONCUSSIVE FORCE AT LIGHTSPEED. ENOUGH TO EQUAL THE PRESSURE INSIDE THE CORE OF 6659.1267 WHITE DWARF STARS.

LIKELY, THIS IS NOT HIS LIMIT SINCE SUPERMAN WAS WEAKENED BY RED SUN RADIATION.

DURABILITY FEAT:

GALAXY

Durability: Galaxy 75%

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For the Power Level Scale, visit the Power Level Wiki.


 
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LINKS

Action Comics Vol 1 847 in DC Database.

Superman, ‘Wonder Woman’ Vol 2 219

 
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IN MIND CONTROL

Superman in the Middle East hovering over the land to stop a war.

SUPERMAN (CLARK KENT)
NEW EARTH

In Wonder Woman (2005) #219, titled “Sacrifice, Part IV of IV”, a mind-controlled Superman performs a super-strength feat. Maxwell Lord mind-controls Superman with the vision that Wonder Woman is Doomsday and that the Man of Steel has to kill it. During the fight, an all-out Superman punches Wonder Woman from the sun to Earth.

How much super-strength does it take for Superman to punch Wonder Woman from the sun to Earth?

*Visit Power Girl, ‘Wonder Woman’ Vol 3 41 for our calculations.

IN THE ISSUE, A MIND-CONTROLLED SUPERMAN PUNCHED WONDER WOMAN IN A PERFECTLY ELASTIC COLLISION OVER 150 BILLION METERS FROM THE SUN TO THE EARTH IN ONE INSTANT.

RELEVANTLY, WONDER WOMAN LOST CONSCIOUSNESS FOR ONE INSTANT. WE THEORIZE THAT THE PUNCH SENT HER AT FASTER-THAN-LIGHT SPEEDS OVER 150 BILLION METERS DISTANCE IN ONE SECOND.

IMPORTANTLY, THE PUNCH GENERATED A TOTAL WORK OF 8.4375*1023 JOULES. SIMILARLY, THE EQUIVALENT OF 0.21938377535 PERCENT THE ENERGY PRODUCED BY THE SUN PER SECOND. ENOUGH TO DESTROY A LARGE COUNTRY.

SUPER-STRENGTH FEAT:

STELLAR

Super Strength: Stellar 58%

For our database entries on DC Power Levels, visit the DC Characters page!

For the Power Level Scale, visit the Power Level Wiki.


 
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LINKS

Wonder Woman Vol 2 219 in DC Database.

Superboy, ‘Infinite Crisis’ Vol 1 6

 
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IN DEATHS AND RESURRECTIONS

SUPERBOY (KON-EL)
NEW EARTH

In Infinite Crisis (2006) #6, titled “Touchdown,” Superboy performs a super strength feat. In the Arctic, Superboy-Prime with the solar-collecting armor has returned to help Alexander Luthor Jr in their search for the perfect Earth. At the end of the battle, Superboy tackles Superboy-Prime into the tower destroying it and sacrificing his life.

How much super strength does it take for Superboy to destroy Alexander Luthor’s tower with his tackle?

IN THE ISSUE, SUPERBOY TACKLED SUPERBOY-PRIME INTO THE TOWER DESTROYING IT AND SACRIFICING HIS LIFE.

RELEVANTLY, THE TOWER OPENED A WORMHOLE TO THE DC MULTIVERSE WHERE ALEXANDER LUTHOR JR WAS CREATING A NEW UNIVERSE. AND BASED ON THE FIRST MONITOR’S DESIGN, THE COSMIC TUNING TOWER CAN WITHSTAND ANTI-MONITOR‘S ANTI-MATTER WAVE THAT WAS DESTROYING THE POSITIVE MATTER UNIVERSE IN CRISIS ON INFINITE EARTHS.

IMPORTANTLY, THOUGH THE 52 PARALLEL UNIVERSES ARE SEPARATED BY TIME, SUPERBOY GENERATED A MULTIVERSAL AMOUNT OF SUPER-STRENGTH IN ORDER TO DESTROY THE TOWER. ENOUGH TO TRAVEL TO THE 52 PARALLEL UNIVERSES OF THE DC MULTIVERSE.

SUPER STRENGTH FEAT:

MULTIVERSAL

Super-Strength: Multiversal 92%

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And for the Power Level Scale, visit the Power Level Wiki.


 
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LINKS

Infinite Crisis Vol 1 6 in DC Database.
Cosmic Tuning Tower in Cass Cain Mainframe Wiki.

Steel, ‘Steel’ Vol 2 #21

 
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IN MAD SCIENCE

STEEL (JOHN HENRY IRONS)
NEW EARTH

In Steel (1995) #21, titled “Stalker,” Steel performs a super strength feat. In Washington D.C., still must stop a terrorist attack masterminded by Metallo. During the battle, Steel knocks off Metallo’s head with his hammer.

How much super strength does it take for Steel to knock off Metallo’s head with a kinetic hammer?

  • In 'Steel' (1995) #21, titled "Stalker," Steel performs a super strength feat. During the battle, Steel knocks off Metallo's head with his hammer. DC Comics.

IN THE ISSUE, STEEL HIT METALLO WITH ABOUT 7942571.52 NEWTONS OF IMPACT FORCE IN AN ELASTIC COLLISION THAT REMOVED HIS 5.054 KILOGRAM HEAD FIVE METERS AWAR FROM HIS BODY.

IMPORTANTLY, STEEL GENERATED 39712857.6 JOULES OF KINETIC ENERGY WITH HIS KINETIC HAMMER. SIMILARLY, STEEL GENERATED 88542021.6202 WATTS OF POWER. ENOUGH TO DESTROY A ROOM.

SUPER STRENGTH FEAT:

CITY BLOCK

Super Strength: City Block 25%

For more information about the Stress Calculator, visit the Omni-Calculator.

Also, for our database entries on DC Power Levels, visit the DC Characters page!

And for the Power Level Scale, visit the Power Level Wiki.


Steel is in Washington D.C. and must stop a terrorist attack masterminded by Metallo. Metallo has a new body and Steel uses a strategy used by Superman in his battles against Metallo: He knocks off Metallo’s head. We will calculate Metallo’s durability in order to estimate Steel’s super strength.

METALLO’S DURABILITY

Typically, Metallo is made of an indestructible steel alloy. We will use Metallo’s feat in ‘Adventures of Superman’ (1992) #491, in order to calculate Metallo’s durability. Here, Metallo’s indestructible metal alloy upgraded by Cerberus actually reflects Superman’s heat vision.
In 'Adventures of Superman' (1992) #491, Metallo's indestructible metal alloy upgraded by Cerberus actually reflects Superman's heat vision.In Adventures of Superman (1992) #491, Metallo’s indestructible metal alloy upgraded by Cerberus actually reflects Superman’s heat vision. AP Photo/DC Comics.

NUMBER CRUNCHING

Metallo’s upgraded steel alloy reflected Superman’s heat vision. Typically, Superman’s heat vision reaches temperatures as hot as the sun’s surface, which is about 5520 degrees C. In real-world scenarios, since Metallo is made from a steel alloy, we can assume Superman’s heat vision here is equal or less than steel’s melting point of 1540 °C. And steel’s heat capacity is 480 J/kg °C.

In addition, we can assume Metallo’s head takes up 1.8 percent of his body mass, as in humans.

Thermal Energy = W on system = (1540 °C-20 °C)(480 J/kg C)(272.155 kg*0.2) = 39712857.6 J.

It takes more than 39712857.6 Joules of energy in order to destroy Metallo’s upgraded steel alloy. This is merely a rough estimate and it is very possible that it would take millions of degrees Celsius, a temperature matching the sun’s core, in order to melt Metallo’s upgraded steel alloy.

Our strategy is to use the Conservation of Energy to calculate the kinetic energy used by Steel’s kinetic hammer to knock off Metallo’s head from the thermal energy or work done on the system.

From 4.4: Momentum And Energy, we find:
Wonsystem=ΔKEsystem⟺FΔx1=1/2m1v12

Since the change in kinetic energy equals the work done on the system, we can calculate the impact force in the elastic collision. The elastic collision caused Metallo’s head to travel five meters from its body.

F = ΔKEsystem/Δx1 = (39712857.6 J)/(5 m) = 7942571.52 N.

Since Steel caused a deformation of Metallo’s body, we calculate the shear stress.

Steel, ‘Steel’ Vol 2 #21

In terms of power output, the head knock-off generated 88542021.6202 W of power.

SUPER-STRENGTH

Steel’s kinetic hammer generated 44125397 Pa of stress knocking off Metallo’s head in an elastic collision. In order to knock off Metallo’s head five meters away, Steel had to generate a Building-Level of Super-Strength.

 
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LINKS

Steel Vol 2 21 in DC Database.
Adventures of Superman Vol 1 491 in DC Database.
4.4: Momentum And Energy in Physics LibreTexts.
Stress Calculator in Omni-Calculator.

Orion, ‘Countdown To Final Crisis’ Vol 1 2

 
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IN COSMIC HIERARCHY

ORION
NEW EARTH

In Countdown To Final Crisis (2008) #2, titled “Darkseid Equals Death”, Orion performs a super strength feat. On this day, Orion comes to Metropolis to fulfill the prophecy and kill Darkseid. At the end of the battle, Orion rips out Darkseid’s heart killing him.

How much super-strength does it take for Orion to rip out Darkseid’s heart?

  • In 'Countdown To Final Crisis' (2008) #2, Orion rips out Darkseid's heart killing him. DC Comics.

IN THE ISSUE, ORION RIPPED OUT DARKSEID’S HEART FROM HIS CHEST.

RELEVANTLY, DARKSEID CAN WITHSTAND THE NEGATIVE GRAVITATIONAL FORCE OF THE UNIVERSE ON THE SOURCE WALL. THOUGH WE DO NOT KNOW HOW MUCH POWER DARKSEID’S HEART GENERATES, WE CAN ASSUME DARKSEID IS DURABLE ENOUGH TO WITHSTAND A UNIVERSAL-LEVEL ATTACK.

IMPORTANTLY, ORION GENERATED 8.477*1071 PASCALS OF SHEAR STRESS. ENOUGH TO SHATTER MULTIPLE GALAXIES.

SUPER STRENGTH FEAT:

UNIVERSAL

Super Strength: Universal 83%

For more information on the Stress Calculator, visit the Omni-Calculator.

Also, for our database entries on DC Power Levels, visit the DC Characters page!

And for the Power Level Scale, visit the Power Level Wiki.


Orion ripped out Darkseid’s heart killing him. We will calculate the shear stress necessary to rip a 15 cm radius hole in Darkseid’s chest in order to estimate Orion’s super-strength.

DARKSEID’S DURABILITY

In Superman/Batman (2004) #13, Superman uses a Boom Tube to travel to the Promethean Galaxy. There, he imprisons Darkseid on the Source Wall. In the DC Universe, the Source Wall used to lie at the edge of the universe.

In Superman/Batman (2004) #13, Superman imprisons Darkseid on the Source Wall.

We will use this feat to estimate Darkseid’s durability.

NUMBER CRUNCHING

Since it took the Source Wall to stop Darkseid, his Durability has been rated as Universal-Level. Let’s calculate the gravitational force that Darkseid can withstand. At a speed of 73000 meters per second, the universe has a kinetic energy of 5.329e+61 Joules. Properly speaking, the total energy is zero since it is canceled by its negative gravitational energy.

Gravitational force = F = W/G = |-(5.329e+61 Joules)/(6.67 x 10-11 Nm2/kg22)| = 7.9895052e+71 N.

Using the Omni-Calculator, we calculate the shear stress necessary to rip a 15 cm radius hole in Darkseid’s chest.

Shear Stress = 8.477*10^71 Pa .

SUPER-STRENGTH

Orion generated 8.477*10^71 Pa of stress to rip a hole through Darkseid’s chest. Orion had to generate a Universal-Level of Super Strength.

 
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LINKS

Countdown to Final Crisis Vol 1 2 in DC Database.
Stress Calculator in Omni-Calculator.
Superman/Batman Vol 1 13 in DC Database.

Aquaman, ‘JLA’ Vol 1 118

 
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IN POWER LEVEL

AQUAMAN (ARTHUR CURRY)
NEW EARTH

In JLA (2006) #118, titled “Crisis of Conscience: Part Four”, Aquaman performs a super strength feat. Despero has restored the Secret Society of Super Villains’ memory of the Justice League of America’s secret identities. With the Justice League of America occupied, Aquaman and Martian Manhunter take on Despero. During the fight, Aquaman punches Despero out of San Diego Bay.

How much super strength does it take for Aquaman to punch Despero out of San Diego Bay?

IN THE ISSUE, AQUAMAN PUNCHED DESPERO ONE MILE ABOVE SAN DIEGO BAY.

RELEVANTLY, FISH ARE KNOWN TO JUMP OUT OF WATER AND DESPERO HAD TO RECEIVE ENOUGH THRUST TO JUMP OUT.

IMPORTANTLY, AQUAMAN GENERATED 7.9008737e+13 NEWTONS OF THRUST. SIMILARLY, THE ABSOLUTE VALUE OF THE POWER OF AQUAMAN’S PUNCH WAS 2.8017622*1016 WATTS. ENOUGH TO DESTROY A CITY.

SUPER-STRENGTH FEAT:

MULTI-CONTINENT

Super-Strength: Multi-Continent 42%

For our database entries on DC Power Levels, visit the DC Characters page!

For the Power Level Scale, visit the Power Level Wiki.


Aquaman punched Despero out of San Diego Bay. We will calculate the thrust required for Despero to jump out of water in order to estimate Aquaman’s super strength.

NUMBER CRUNCHING

At 18 meters deep, the pressure on Despero is 1823850 Newtons. When we calculate the thrust, we find the force necessary to move 2440.5 m3 of volume of water across 1627 meters, that is, 1 mile high from 18 meters of seawater depth.

Though the punch is a collision, we will use Despero jumping out of water like a fish, since the punch sent him a mile above San Diego Bay.

From The Royal Society, we find their study on fish jumping out of water. First, we calculate the maximum velocity U0.

U0 = ((H)(2g))^(1/2) = ((18 m + 1609 m)(2 * 9.81 m/s^2))^(1/2) = 178.666560945 m/s.
Fout ≈ mb(z/L)g = (386 kg*9.81 m/s)((18 m + 1609 m)/(2.46888 m)) = 2495421.33275 N.
Ff=mf(z)g+(d/dt)(mfz˙) = -(48855567275 kg)(9.81 m/s^2) + (48855567275 kg)(1609 m +18 m)/(1 s) = 7.9008735e+13 N.
mbz¨=−Fout−Ff = -2495421.33275 N – 7.9008735e+13 N = -7.9008737e+13 N.

Finally, we calculate the power of the punch.
P = FU0 = (-7.9008737e+13 N * 354.614228141 m/s) = -2.8017622e+16 W.

SUPER-STRENGTH

Aquaman generated at least 7.9008737e+13 N of thrust to punch Despero out of San Diego Bay. Aquaman had to generate a Multi-Continent-Level of Super-Strength.

 
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Martian Manhunter, ‘JLA’ Vol 1 75

 
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IN POWER LEVEL

MARTIAN MANHUNTER (J’ONN J’ONNZ)
PRIME EARTH

In JLA (2003) #75, Martian Manhunter performs a super strength feat. At the conclusion of JLA: The Obsidian Age, the Justice League must save the Earth from the Atlantean witch Gamemnae. In order to save the world, J’onn J’onnz, Superman and Wonder Woman push the Earth back into orbit with Manitou Raven’s spell on the magic lasso.

How much super strength does it take for Martian Manhunter to push the Earth back into orbit?

In JLA (2003) #75, Superman, Wonder Woman and Martian Manhunter pull the Earth back into orbit with the magic lasso.
In JLA (2003) #75, Martian Manhunter performs a super strength feat. In order to save the world, J’onn J’onnz, Superman and Wonder Woman push the Earth back into orbit with Manitou Raven’s spell on the magic lasso. DC Comics.

 
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IN THE ISSUE, MARTIAN MANHUNTER, SUPERMAN AND WONDER WOMAN PUSHED THE EARTH BACK INTO ORBIT.

RELEVANTLY, THEY HAD TO ACCELERATE THE EARTH TO 9.81 METERS PER SECOND SQUARED AND MARTIAN MANHUNTER GENERATED A THIRD OF THE FORCE.

IMPORTANTLY, MARTIAN MANHUNTER GENERATED 1.9568253*1025 NEWTONS OF FORCE. SIMILARLY, 552.775508475 TIMES THE GRAVITATIONAL FORCE OF THE SUN ON THE EARTH.

SUPER-STRENGTH FEAT:

MULTI-SOLAR SYSTEM

Super Strength: Multi-Solar System 67%

For our database entries on DC Power Levels, visit the DC Characters page!

For the Power Level Scale, visit the Power Level Wiki.


Martian Manhunter, Superman and Wonder Woman pushed New Earth back into orbit with the help of Manitou Raven who put a spell on the magic lasso to increase its size to more than the radius of the Earth. We will calculate the force required to push the Earth into orbit to estimate Martian Manhunter’s super strength.

NUMBER CRUNCHING

Martian Manhunter, Superman and Wonder Woman pushed the Earth back into orbit. Though the magic lasso was increased to planetary size, it did not supply the super strength to achieve this feat. We will divide the force required to push the Earth by 3, since we can assume they worked equally.

The orbit of the Earth around the sun requires a gravity of 9.8 m/s2. In order to move Earth, it is necessary to move a mass of 5.972*1024 kg.

Let’s calculate the force.

F = ma = (5.972*10^24 kg * 9.8 m/s2 )/3 = 1.9568253*1025 N.

SUPER-STRENGTH

Martian Manhunter generated at least 1.9568253*1025 N of force to push the Earth into orbit. Martian Manhunter had to generate a Multi-Solar System-Level of Super-Strength since he likely generated 552.775508475 times greater than the gravitational force of the sun on Earth.

 
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Martian Manhunter, ‘JLA’ Vol 1 #85

 
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You’re not too sensitive. You’re allowed to feel your feelings.

Dr. Janina Scarlet

IN EVOLUTION

MARTIAN MANHUNTER (J’ONN J’ONNZ)
PRIME EARTH

In JLA (2003) #85, Martian Manhunter performs an energy projection feat. At the beginning of JLA: Trial By Fire, the Justice League must investigate a rogue telepath who has created international incidents. In order to help locate the rogue telepath, a J’onn J’onnz on leave of absence scans all the minds on Earth.

How much energy projection does it take for Martian Manhunter to scan all the minds on Earth?

 
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IN THE ISSUE, MARTIAN MANHUNTER SCANNED ALL THE MINDS ON EARTH TO LOCATE THE ROGUE TELEPATH.

RELEVANTLY, THE STORAGE CAPACITY OF THE HUMAN BRAIN IS UP TO 2.5*1015 BYTES.

IMPORTANTLY, MARTIAN MANHUNTER GENERATED 8.1414023*1026 WATTS OF POWER. SIMILARLY, 2.11684927197 TIMES THE POWER OUTPUT OF THE SUN. ENOUGH TO SHATTER MULTIPLE CONTINENTS.

ENERGY PROJECTION FEAT:

STELLAR

Energy Projection: Stellar 58%

For our database entries on DC Power Levels, visit the DC Characters page!

For the Power Level Scale, visit the Power Level Wiki.


Martian Manhunter scanned all the minds on Earth. We will use the storage capacity of the human brain to estimate Martian Manhunter’s energy projection.

NUMBER CRUNCHING

There are 7,874,965,825 people on 21st century Earth. Refer to this article on the storage capacity of the human brain.

Total Human Storage Capacity In Bytes = (2.5*1015 bytes)(7,874,965,825 humans) = 1.9687415*1025 bytes*humans.

Biochemical Energy = (1.9687415*1025 bytes*humans)(1 J/K)(310.15 K/human)/(0.125 bytes) = 4.8848414*1028 J.

Power = (4.8848414*1028 J)/(60 s) = 8.1414023*1026 W.

ENERGY PROJECTION

Martian Manhunter generated at least 8.1414023*1026 W of power to scan all the minds on Earth. Martian Manhunter had to generate a Stellar Level of Energy Projection since he likely generated 2.11684927197 times greater than the energy produced by the sun every second.

 
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