In Mighty Thor (1993) #468, titled “Distant Thunder”, Thor performs a super strength feat. In the Blood and Thunder storyline, Thor is struck by the Warrior Madness and battles Beta Ray Bill and Lady Sif. During the battle, Thor knocks-out BRB with a hammerstrike, destroying the asteroid they were battling on.
How much super-strength does it take for Thor to shatter a main belt asteroid knocking out Beta Ray Bill?
IN THE ISSUE, THOR SHATTERED THE MILE-WIDE MAIN BELT ASTEROID WITH A HAMMERSTRIKE KNOCKING OUT BETA RAY BILL.
RELEVANTLY, APOLLO IS MILE-WIDE AND WEIGHS 2*1012 KILOGRAMS. IN ADDITION, AN ASTEROID CAN TRAVEL AT 25000 METERS PER SECOND IN SPACE.
IMPORTANTLY, THOR GENERATED 1.4499401*1021 NEWTONS OF FORCE. SIMILARLY, THE EQUIVALENT OF ONE PERCENT OF THE PRESSURE AT THE CORE OF A WHITE DWARF STAR. ENOUGH TO SHATTER A LARGE ISLAND.
DURABILITY FEAT:
STELLAR
Super Strength: Stellar 58%
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Warrior Madness Thor destroyed a main belt asteroid knocking out Beta Ray Bill. We will calculate the kinetic energy of a main belt asteroid to estimate Thor’s super-strength.
THOR’S SUPER-STRENGTH
In Blood and Thunder, Thor succumbs to the Warrior Madness. Importantly, his strength is increased tenfold. At the same time, we can assume the asteroid is a main belt asteroid since his following battle in the vicinity against Silver Surfer lands them on a planet. See Thor, Silver Surfer Vol 3 #86.
NUMBER CRUNCHING
According to NASA, the Apollo asteroid is one mile wide and weighs 2*1012 kg. Moreover, asteroids can reach speeds of 25000 meters per second.
We need to calculate the asteroid’s kinetic energy in order to estimate Thor’s super-strength. KE = (1/2)((2*1012 kg)(250002 m/s) = 6.25e+20 J.
Then, we use Mjolnir’s length and height of 0.3048 m to estimate the force. W = Fd. F = W/d = (6.25*1020 J)/((0.3048*0.3048) + (0.3048*0.3048)1/2)) = 1.4499401e+21 N.
SUPER-STRENGTH
Thor generated 1.4499401e+21 Newtons of force to shatter the main belt asteroid. Thor had to generate a Stellar-Level of Durability.
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