Feat: Silver Surfer, ‘Silver Surfer’ #9

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IN SUPERHERO BATTLES

SILVER SURFER (NORRIN RADD)
EARTH-616

In ‘Silver Surfer’ (2015) #9 titled “Slingshot”, Silver Surfer performs a super strength feat. Galactus has come to Newhaven in order to consume it. To fight Galactus, Silver Surfer anchors his board at the opposite pole of the moon, moves it and slams it into Galactus at superluminal speeds.

How much super strength does it take for Silver Surfer to move the moon at superluminal speeds?

In 'Silver Surfer' (2015) #9, Silver Surfer moves the moon out of orbit and slams it into Galactus at superluminal speed.
In ‘Silver Surfer’ (2015) #9, Silver Surfer moves the moon out of orbit and slams it into Galactus at superluminal speed. AP Photo/Marvel Comics.

SILVER SURFER MOVED THE MOON AT SUPERLUMINAL SPEEDS AND SLAMMED IT INTO GALACTUS WITH 3.3064529*1039 JOULES OF KINETIC ENERGY.

SILVER SURFER GENERATED 8.5993573*1030 NEWTONS OF FORCE, THE EQUIVALENT OF 0.24291969774 PERCENT THE MILKY WAY’S TOTAL GRAVITATIONAL FORCE. ENOUGH TO SHATTER A SMALL STAR.

SUPER STRENGTH FEAT:

GALAXY

Super Strength: Galaxy 75%

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Head over to Silver Surfer’s New Powers: Silver Surfer Black Conclusion | Comics Explained by Comics Explained.

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Silver Surfer moves the moon at superluminal speeds.

We will calculate the kinetic energy to estimate the force.

NUMBER CRUNCHING

Let’s calculate the kinetic energy.

KE = (1/2)(mc2) = (7.34767309 × 1022 kg x 0.5)(3*108 m/s)^2) = 3.3064529*1039 J.

Let’s assume Galactus is in low orbit, around 1000 km above Newhaven and the moon is 384.4 million meters away.

W = Fd = KE. F = KE/d = (3.3064529*1039 J)/(384.4*106 m + 100000 m) = 8.5993573*1030 N.

SUPER STRENGTH



Silver Surfer generated 8.5993573*1030 N of force to move the moon at superluminal speeds slamming it into Galactus. Silver Surfer had to generate a Galaxy Level of Super Strength since he likely hit Galactus with a force 0.24291969774 percent the total gravitational force of the Milky Way.

Toggle the Toggle Arrow below to view the calculations.

Calculations for Silver Surfer, ‘Silver Surfer’ #9

Mass Of The Moon = 7.34767309 × 10^22 kg.
Number Of Suns In Milky Way = 100*10^9 suns.
Gravitational Force Of Milky Way = (3.54*10^22 N)(100*10^9 suns) = 3.54*10^33 N.

KE Of Moon = (1/2)(mc2) = (7.34767309 × 1022 kg x 0.5)(3*10^8 m/s)^2) = 3.3064529*10^39 J.
W = Fd = KE. F = KE/d = (3.3064529*10^39 J)/(384.4*106 m + 100000 m) = 8.5993573*10^30 N.
Comparison = (8.5993573*10^32 N)/(3.54×10^33 N) = 0.00242919697.

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SOURCES

Silver Surfer Vol 7 9 in Marvel Database

Feat: She-Hulk, ‘Avengers’ #500

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IN CRISES

SHE-HULK (JENNIFER WALTERS)
EARTH-616

In ‘Avengers’ (2004) #500, titled “Avengers Disassembled, Chaos (Part I of IV)”, She-Hulk performs a super strength feat. Scarlet Witch wants revenge on the Avengers and triggers Vision‘s sleeper program which unleashes five Ultron drones. During the battle, a Scarlet Witch mind-controlled She-Hulk tears Vision in half.

How much super strength does it take for She-Hulk to rip Vision in half?

In 'Avengers' (2004) #500, a mind-controlled She-Hulk by Scarlet Witch rips Vision in half.
In ‘Avengers’ (2004) #500, She-Hulk performs a super strength feat. During the battle, a Scarlet Witch mind-controlled She-Hulk tears Vision in half. AP Photo/Marvel Comics.

SHE-HULK RIPPED VISION IN HALF. VISION’S SYNTHEZOID BODY CAN WITHSTAND VIBRANIUM BULLETS WITH MORE THAN 4.9838*1043 PSI OF STRESS.

SHE-HULK GENERATED MORE THAN HALF OF 3.2816063*1047 NEWTONS OF FORCE, THE EQUIVALENT OF 9.3227452*1024 SOLS. ENOUGH TO SHATTER A SOLAR SYSTEM.

SUPER STRENGTH FEAT:

GALAXY

Super Strength: Galaxy 75%

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A Scarlet Witch mind-controlled She-Hulk ripped Vision in half.

We will use Vision’s durability to estimate She-Hulk’s super strength.

VISION’S DURABILITY


In ‘Avengers’ (1969) #62, Black Panther flies Hawkeye, Vision and Black Knight to Wakanda. There, they are met by Wakanda soldiers who open fire on them on M’baku’s orders. During the fight, Vision withstands Wakandan Vibranium bullets.

In ‘Avengers’ (1969) #62, Vision withstands Wakandan Vibranium bullets. AP Photo/Marvel Comics.

In ‘Marvel Super Heroes Secret Wars’ (1984) #8, Captain America uses his Vibranium alloy shield to survive the Human Torch’s nova flame as the Fantastic Four superhero defeats Ultron.

In 'Marvel Superheroes Secret Wars' #8, the Human Torch unleashes the nova flame on Ultron. In ‘Marvel Superheroes Secret Wars’ (1984) #8, the Human Torch unleashes the nova flame on Ultron. AP Photo/Marvel Comics

We will use these feats to calculate Vision’s durability.

NUMBER CRUNCHING



First, let’s estimate the durability of Captain America’s Vibranium shield. Captain America’s Vibranium shield can withstand the intensity of a nova flame. In Feat: Superman, ‘DCeased’ #6, I calculated the energy released by a supernova to be 1.8*10^47 J. Cap’s shield is actually 32.5% dense in Vibranium. Let’s calculate the durability of Vibranium in terms of energy.

Durability of Vibranium = (0.325)(1.8*10^47 J) = 5.85*1046 J.

Vision’s synthezoid body is made up of Horton cells. Let’s calculate the density of Vision’s body.

Density Of Vision’s Body = (136.08 kg)/(1.91 m*1 m*0.5 m) = 142.492146597 kg/m3.

Let’s multiply the density times the number of Horton cells.

Vision’s Durability = (5.85*1046 J)(3*1015 Horton cells*10-12 kg/m3)/(1 Horton cell*142.492146597 kg/m3) = 3.2816063*1048 J.

Since the Vibranium bullets did not budge Vision, the super strength needed to affect his durability is at least 3.2816063*1047 N or 49838390581938219895287958115183246073298429 PSI.



DURABILITY



She-Hulk generated more than half of 3.2816063*1047 N of force in order to affect Vision’s durability. Vision had to generate a Galaxy Level of Super Strength since she likely ripped Vision with a force 9.3227452*1024 times greater than the gravitational force of the sun on Earth.

Toggle the Toggle Arrow below to view the calculations.

Calculations for She-Hulk, ‘Avengers’ #500

Gravitational Force Of Sun On Earth = 3.54*10^22 N

Durability of Vibranium = (0.325)(1.8*10^47 J) = 5.85*10^46 J.
Density Of Vision’s Body = (136.08 kg)/(1.91 m*1 m*0.5 m) = 142.492146597 kg/m^3.
Vision’s Durability = (5.85*1046 J)(3*1015 Horton cells*10-12 kg/m^3)/(1 Horton cell*142.492146597 kg/m^3) = 3.2816063*10^48 J.
Comparison = (3.2816063*10^47 N)/(3.54*10^22 N) = 144477.635593.

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SOURCES

Avengers Vol 1 500 in Marvel Database.
Avengers Vol 1 62 in Marvel Database.
Marvel Super Heroes Secret Wars Vol 1 8 in Marvel Database.

Feat: Nightwing, ‘Outsiders’ #3

Home » Super strength

IN GOVERNMENT CONSPIRACY

NIGHTWING (RICHARD GRAYSON)
NEW EARTH

In ‘Outsiders’ (2003) #3, titled “Role Call, Part Three: Joke’s On You”, Nightwing performs a super strength feat. The Outsiders are thwarting a Gorilla City attack on New York that serves as a diversion for Joker to kidnap and torture the president, Lex Luthor. During the battle, Nightwing draws blood on Gorilla Grodd twice with his Eskrima sticks.

How much super strength does it take for Nightwing to draw blood on Gorilla Grodd twice with his Eskrima sticks?

In 'Outsiders' (2003) #3, Nightwing draws blood on Gorilla Grodd twice with his wingdings.
In ‘Outsiders’ (2003) #3, Nightwing performs a super strength feat. During the battle, Nightwing draws blood on Gorilla Grodd twice with his wingdings. AP Photo/DC Comics. AP Photo/DC Comics.

NIGHTWING HIT GORILLA GRODD TWICE DRAWING BLOOD. GRODD’S SKIN CAN WITHSTAND 551996 PSI OR 3805879139 PASCALS OF STRAIN, 0.42287545988 TIMES AS DURABLE AS BONE.

NIGHTWING GENERATED 27488970 NEWTONS OF TOTAL FORCE, THE EQUIVALENT OF 3089.8831569002514 TONS. THIS IS NOT HUMANLY FEASIBLE AND LIKELY REQUIRED MARTIAL ARTS WITH PRESSURE POINTS.

SUPER STRENGTH FEAT:

BUILDING

Super Strength: Building 17%

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Head over to History Of Nightwing! by Variant Comics.

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Nightwing and Outsiders are fighting Gorilla Grodd and the army of Gorilla City in New York. In order to interrogate Gorilla Grodd, Nightwing hits him twice on the face, drawing blood.

We will estimate Gorilla Grodd’s durability in order to rate Nightwing’s super strength.

GORILLA GRODD’S DURABILITY


In ‘Flash’ (1991) #47, Vixen, Flash (Wally West) and Pied Piper are held captive by Gorilla Grodd. Flash frees himself from Grodd’s collar used for mind control and hits him with a speed blitz of three thousand punches.

In 'Flash' (1991) #47, Flash hits Gorilla Grodd with a speedblitz of three thousand punches.In ‘Flash’ (1991) #47, Flash hits Gorilla Grodd with a speedblitz of three thousand punches. AP Photo/DC Comics.

We will use this feat to calculate Nightwing’s super strength feat.

NUMBER CRUNCHING



This is a stress and strain problem. Let’s punch values into the Stress Calculator, on the Omni-Calculator. We get the following results. Refer to the Calculations Toggle Arrow to view the calculations for Area (A) and Force (F).


Nightwing, ‘Outsiders’ #3

Let’s calculate Nightwing’s first hit. The first hit is with a variable force at an angle of 45 degrees. Let’s calculate the acceleration knowing that the Eskrima stick weighs 0.425243 kg.

a = F/m = (15000000 N)/(0.425243 kg) = 35273949.2478 m/s2.

Arc Length = θ × r = (45° × π/180 rad*15000000 N)/(1 rad) = 11780970 N.

Then we calculate the second hit.

Arc Length = θ × r = (60° × π/180 rad*15000000 N)/(1 rad) = 15708000 N.

Total Super Strength = 27488970 N = 3089.8831569002514 Tons.

SUPER STRENGTH



Nightwing generated 27488970 N of total force making Gorilla Grodd bleed. Nightwing had to generate a Building Level of Super Strength since he hit Gorilla Grodd with 3089.8831569002514 Tons. This is not humanly feasible and is likely a result of martial arts with pressure points.

Toggle the Toggle Arrow below to view the calculations.

Calculations for Nightwing, ‘Outsiders’ #8

Metahuman Strength = 1000 kg = m.

Area = (pi)(10 cm)(5 cm) = 157.07963 cm^2.
Force = ma = (1000 kg)(3000 punches)(5 m/s^2) = 15000000 N.
a = F/m = (15000000 N)/(0.425243 kg) = 35273949.2478 m/s2.
Arc Length First Hit = θ × r = (45° × π/180 rad*15000000 N)/(1 rad) = 11780970 N.
Arc Length Second Hit = θ × r = (60° × π/180 rad*15000000 N)/(1 rad) = 15708000 N.
Total Super Strength = (11780970 N + 15708000 N) = 27488970 N.
Super Strength In Tons = (27488970 N * 1 ton)/(9964.016384 N) = 3089.8831569002514 Tons.
Ratio Of Young’s Modulus = (3805879139 Pa)/(9000000000 Pa) = 0.42287545988. https://openstax.org/books/university-physics-volume-1/pages/12-3-stress-strain-and-elastic-modulus

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SOURCES

Outsiders Vol 3 3 in DC Database.
The Flash #47 in Comic Vine.

Feat: Shazam, ‘Justice League of America’ #8

Home » Super strength

IN SUPERHERO BATTLES

SHAZAM (BILLY BATSON)
PRIME EARTH

In ‘Justice League of America’ (2013) #8, titled “Paradise Lost”, Shazam performs a super strength feat. The Justice League has been imprisoned in prisons that are actually illusions created by the Crime Syndicate with technology. Finding Shazam’s prison, J’onn is engaged in a fight. During the fight, Shazam at full power punches Martian Manhunter who is at less than half strength.

How much super strength does it take for Shazam to punch Martian Manhunter at less than half strength?

In ‘Justice League’ (2013) #8, titled “Paradise Lost”, Martian Manhunter performs a super strength feat. During the fight, Shazam at full power punches Martian Manhunter who is at less than half strength. AP Photo/DC Comics.

SHAZAM STATED TO BE AT FULL POWER PUNCHED MARTIAN MANHUNTER 10 METERS AWAY DRAWING BLOOD.

SHAZAM GENERATED 5.1145083*10^27 NEWTONS OF FORCE, WITH 5.1145083*10^28 JOULES OF WORK, THE EQUIVALENT OF 144477.635593 TIMES THE SUN’S GRAVITATIONAL FORCE ON PRIME EARTH. ENOUGH TO SHATTER A LARGE PLANET.

SUPER STRENGTH FEAT:

SOLAR SYSTEM

Super Strength: Solar System 67%

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Head over to How Powerful Is Shazam? by Variant Comics.

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Shazam has been imprisoned in a prison by the Crime Syndicate that turns out to be an illusion. Martian Manhunter states Shazam is at full power whereas J’onn is at less than half strength.

We will use this statement to estimate J’onn being at less than half strength.

MARTIAN MANHUNTER’S SUPER STRENGTH



In ‘Action Comics’ (2014) #34, Superman and Martian Manhunter together manage to slow the descent of the Brainiac Mothership that was descending on Earth at 36000 miles per hour.

In ‘Action Comics’ (2014) #34, Superman and Martian Manhunter together slow down the Brainiac Mothership that was descending on Earth at 36000 miles per hour. AP Photo/DC Comics.

We will use this feat to calculate Martian Manhunter at less than half strength.

NUMBER CRUNCHING



In the issue, it is stated that the Brainiac Mothership is bigger than Earth. Let’s estimate it to be twice the size of Earth. K2-18b exoplanet has been found to be 2.6 times the Earth’s radius and 8.6 times its mass. If we assume the Brainiac Mothership to be the size of K2-18b, then its mass is roughly 8.6 times the mass of Earth. Let’s calculate the kinetic energy of the Brainiac Mothership.

KE = (1/2)(mv2) = (5.972 × 10^24 x 8.6)(16093.44)^2) = 1.3301972*10^34 J. Let’s calculate the gravitational force F. Then, since both Superman and Martian Manhunter contributed, we divide the force by two.

F = Gm1m2/r2 = (6.67 × 10^-11 m3/kg s2)(8.6)(5.972 × 10^24 kg)^2)/(2*10^12 m) = 1.0229017*10^28 N.

To find the strength of Martian Manhunter at less than half strength, we divide by two.

Shazam at full power = Martian Manhunter at less than half strength = 1.0229017*10^28 N/2 < 5.1145083*10^27 N.

Then we calculate the work done punching J’onn 10 meters away which is 5.1145083*10^28 J. This super strength is more than the gravitational force of the sun on Earth. This means Shazam is less strong than Martian Manhunter at half power but probably at least Planetary Level.

SUPER STRENGTH



Shazam generated 5.1145083*10^27 N of force at full power to punch Martian Manhunter at less than half strength 10 meters away making him bleed. Shazam had to generate a Solar System Level of Super Strength since he likely hit Martian Manhunter with a punch 144477.635593 times greater than the gravitational force of the sun on Earth.

Toggle the Toggle Arrow below to view the calculations.

Calculations for Shazam, Justice League of America’ #8

Mass Of Sol = 5.972 × 10^24 kg.
Gravitational Force Of Sun On Earth = 3.54*10^22 N

KE = (1/2)(mv2) = (5.972 × 10^24 x 8.6)(16093.44)^2) = 1.3301972*10^34 J.
F = Gm1m2/r2 = (6.67 × 10^-11 m3/kg s2)(8.6)(5.972 × 10^24 kg)^2)/(2*10^12 m) = 1.0229017*10^28 N.
Shazam at full power = Martian Manhunter at less than half strength = 1.0229017*10^28 N/2 < 5.1145083*10^27 N.
Work done = 5.1145083*10^27 N * 10 m = 5.1145083*10^28 J.
Comparison = (5.1145083*10^27 N)/(3.54*10^22 N) = 144477.635593.

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SOURCES

Justice League of America Vol 3 8 in DC Database.
This exoplanet, twice the size of the Earth, may have right conditions for life in The Economic Times.

Feat: Superman, ‘Justice League’ #25

IN COSMIC HIERARCHY

SUPERMAN (CLARK KENT)
PRIME EARTH

In ‘Justice League’ (2019) #25, titled “The Sixth Dimension! Conclusion,” Superman performs a super strength feat. In a battle against the World Forger, Superman sundips then breaches the Sixth Dimension and shatters the Forger’s Multiverse creation with a dimension-shattering punch.

How much super strength does it take for Superman to shatter the World Forger’s Multiverse creation with a dimension-shattering punch?

SUPERMAN SUNDIPPED TO TIME TRAVEL AS A WAVE FUNCTION 20 BILLION YEARS TO THE BIG BANG IN THE SIXTH DIMENSION TO DESTROY THE WORLD FORGER’S MULTIVERSE.

SUPERMAN HAD TO GENERATE AN INFINITE AMOUNT OF ENERGY FROM HIS DIMENSION-SHATTERING PUNCH, IN ORDER TO DESTROY THE 19.7265937 BILLION LIGHT YEARS MULTIVERSE CREATED BY THE WORLD FORGER.

SUPER STRENGTH FEAT:

BOUNDLESS

                       

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Superman travels faster than light from his prison on Prime Earth to the Sixth Dimension. Superman travels so fast that he becomes a line where all timelines are present to him and he arrives at the time of a new Big Bang. Superman destroys the World Forger’s Sixth Dimension Multiverse creation with a dimension-shattering punch.

We will use string theory to calculate the energy necessary to travel to the Sixth Dimension according to the Many-Worlds Interpretation. Please Toggle the Toggle Arrow below to see the calculations.

NUMBER CRUNCHING

In order to calculate the energy necessary to travel to the Sixth Dimension, we must calculate the universal wavefunction interpretation of string theory. According to ‘Justice League’ (2019) #22, the multiverse created by Perpetua and her three beings is 20 billion years old. We can assume the World Forger in the Sixth Dimension created the Multiverse with a Big Bang 20 billions years old. In order to dimension travel to the Sixth Dimension, Superman had to travel faster than light 20 billion years old into the past of the DC Universe. For all intents and purposes, we can assume Superman travelled at the speed of light. The equation to calculate the wave function is below:

ψ(L,T) = exp(i ʃ0Tdτ ʃ0 Ldσ/lptp) ψ(0,0).

Integrating the double integral we obtain the integral of the inside function first:

ψ(L,T) = exp(i ʃ0Tdτ (σ/lptp)|0 1.8662410^26 = exp(i ʃ0Tdτ (1.8662410^26 m)/(1.616*10^-35 m * 5.39*10^-44 s).

Then we obtain the integral of the outside function.

ψ(L,T) = exp(i ʃ0 9.331210^15 (τ)(2.142582e+104 s^-1) = exp(9.331210^15 s)(2.142582e+104 s^-1) = ∞.

We get an infinite amount of energy.

SUPER-STRENGTH

Superman generated an infinite amount of energy in order to become a wave function at the Planck scale and time travel to the Sixth Dimension.

Superman had to generate a Boundless Level of Super Strength since he essentially hit the World Forger’s Multiverse with an infinite amount of energy from time travel to the Big Bang.

Toggle the Toggle Arrow below to view the calculations.

Calculations for Superman, ‘Justice League’ #25

ψ(L,T) = exp(i ʃ0Tdτ ʃ0 Ldσ/lptp) ψ(0,0).
Planck length = lp = 1.616*10^-35 m.
Planck time = tp = 5.39*10^-44 s.
T = age of causal horizon = (20*10^9 years)(12 months*30 days*24 hr*3600 s) = 9.3312*10^15 s
L = length of causal horizon = vt = (3*10^8 m/s)(9.3312*10^15 s) = 1.86624*10^26 m = 19.7265937*10^9 light years.

ψ(L,T) = exp(i ʃ0Tdτ (σ/lptp)|0 1.86624*10^26 = exp(i ʃ0Tdτ (1.86624*10^26 m)/(1.616*10^-35 m * 5.39*10^-44 s) = exp(i ʃ0Tdτ (2.142582e+104 s^-1) = exp(i ʃ0 9.3312*10^15 (τ)(2.142582e+104 s^-1) = exp(9.3312*10^15 s)(2.142582e+104 s^-1) = ∞.


SOURCES

Justice League Vol 4 25 in DC Database.
The Universal Wave Function Interpretation Of String Theory in EPF Web Of Conferences.
Justice League Vol 4 22 in DC Database.

Feat: Batman, ‘Batman vs The Incredible Hulk’ #1

IN POWER LEVEL

BATMAN (BRUCE WAYNE)
EARTH-ONE

In ‘Batman vs The Incredible Hulk’ (1995) #1, titled “The Monster and The Madman”, Batman performs a fighting skills feat. Hired by the Shaper of Worlds, Joker has robed one of Bruce Wayne’s labs and turned Hulk against Batman. During the battle, Batman kicks Hulk at the solar plexus, depriving him of air and making the monster susceptible to sleeping gas.

How much fighting skill does it take for Batman to kick Hulk at the solar plexus, depriving him of air?

In 'Batman vs The Incredible Hulk' Batman performs a super strength feat. During the battle, Batman kicks Hulk at the solar plexus, depriving him of air and making the monster susceptible to sleeping gas.
In ‘Batman vs The Incredible Hulk’ Batman performs a super strength feat. During the battle, Batman kicks Hulk at the solar plexus, depriving him of air and making the monster susceptible to sleeping gas. AP Photo/DC Comics.

BATMAN KICKED HULK AT THE SOLAR PLEXUS CAUSING HIM TO NEED 7.0555752*10^15 LITERS OF AIR.

BATMAN GENERATED THE EQUIVALENT OF 1.545431*10^18 CALORIES BURNED OR 6.4660831*10^21 JOULES WITH HIS PRESSURE POINT KICK, STRONGER THAN 9.2958253*10^12 MEN AND 2.5 TIMES THE ENERGY RECEIVED BY THE EARTH, ENOUGH TO DESTROY A SMALL COUNTRY.

FIGHTING SKILLS FEAT:

WARRIOR MADNESS

                       

Please visit the Battle Ranker: The Competition for the Fighting Skills Point System.

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Head over to How Strong is Batman With Prep Time – Battle Suits – DC COMICS – Bruce Wayne by IvaN The UnStoppable.

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Batman is cornered by the Hulk and has nowhere to go. In order to even the odds, he triggers sleeping gas. However, Hulk, displaying some measure of intelligence, holds his breath. Batman states that “Hulk can hold his breath from now till next Christmas.”1

We will use this statement to estimate Hulk’s vital capacity. This will help us determine the strength of Batman’s kick at Hulk’s solar plexus.

NUMBER CRUNCHING

The Hulk possesses an organ that allows him to breathe underwater. At the same time, his lung capacity allows him to hold his breath for an indefinite amount of time. Vital capacity is a measure of how much air our lungs can retain, when holding our breath.In this feat, Hulk holding his breath is actually a function of his vital capacity.

It must be noted, that though Hulk is Bruce Banner’s transformation into a monster, we can still assume that he is an oversized human to simplify our calculations. In Investigation: What Factors Affect Lung Capacity we use a graph in order to estimate lung capacity (L) from the change in diameter (cm) after exhaling into a balloon.

Below is the graph.

Batman, ‘Batman vs The Incredible Hulk’ #1

Using a program, I obtained the equation of the best-fit parabola:

Equation of parabola = 19.9124x^2 − 212.429x + 448.505.

According to Batman, Hulk can hold his breath for six months. Let’s obtain the ratio of breath holding for a human, which is between 30s and 90s.

Ratio of Breath Holding = (6 months*30 days*24 hours*3600 seconds)/(90 seconds) = 172800.

Next, we use the fact a human can retain 6 Liters of air to compute the diameter at 22.8 cm. To find Hulk’s ballon diameter, we multiply by our ratio.

Balloon Diameter = (172800*22.8) = 3939840 cm.

Now we can find Hulk’s vital capacity.

Vital Capacity = (19.9124*3939840*3939840 – 212.429*3939840 + 448.505) = 3.0908619*10^14 Liters.

The metabolism of breathing is burning about 5000 calories. We can use this to find the energy in Joules used by Hulk’s vital capacity.

Energy in Joules = (5000 calories*3.0908619*10^14 Liters*4184 J)/(1 calorie) = 6.4660831*10^21 Joules.

Let’s calculate the calories burned by Batman during a 10 minute martial arts activity.

Batman, ‘Batman vs The Incredible Hulk’ #1

If we divide the super strength of Batman’s kick by the metabolic expenditure in 10 minutes, we get the following: = (6.4660831*10^21 J*1 cal)/(166250 cal*4184 J) = 9.2958253*10^12.

FIGHTING SKILLS

In order to deprive Hulk of air, Batman had to generate a kick of 6.4660831*10^21 Joules of energy. That is a mammoth amount of energy. In comparison, the Earth receives 430*10^18 Joules/hr of energy from the sun.

Batman had to generate a Planetary Level of Super Strength in his kick. This is not humanly feasible and shows that Batman likely used martial arts and chi to kick Hulk at a pressure point, namely the solar plexus.

According to Battle Ranker: The Competition, since Batman generated a Planetary Level kick, he can defeat 500000001-10E13 men in combat. Therefore, Batman generated a Warrior Madness Level of Fighting Skills with his pressure point kick.

Toggle the Toggle Arrow below to Show/Hide the calculations.

Calculations for Batman, ‘Batman vs The Incredible Hulk’ #1

Equation of parabola = 19.9124x^2 − 212.429x + 448.505.

(6 months*30 days*24 hours*3600 seconds)/(90 seconds) = 172800.
Balloon Diameter = (172800*22.8) = 3939840 cm.
Vital Capacity = (19.9124*3939840*3939840 – 212.429*3939840 + 448.505) = 3.0908619*10^14 Liters.
Calories Burned = (5000 calories *3.0908619*10^14 Liters) = 1.545431*10^18 calories.
Energy in Joules = (5000 calories*3.0908619*10^14 Liters*4184 J)/(1 calorie) = 6.4660831*10^21 Joules.
Ratio Per Energy Received By Earth = (6.4660831*10^21 J*10 minutes)/(430*10^18 J*60 minutes) = 2.50623375969.
Ratio Of Super-Strength/Metabolic Expenditure in 10 Minutes = (6.4660831*10^21 J*1 cal)/(166250 cal*4184 J) = 9.2958253*10^12.
Ratio Per Tons Of TNT = (6.4660831*10^21 J)/(4.2*10^9 J) = 1.5395436*10^12.


SOURCES

Batman vs. The Incredible Hulk #1 in Comic Vine.
Investigation: What Factors Affect Lung Capacity in The Biology Corner.

FOOTNOTES

  1. Batman vs The Incredible Hulk #1.

Feat: Steel, ‘Steel’ #21

IN MAD SCIENCE

STEEL (JOHN HENRY IRONS)
NEW EARTH

In ‘Steel’ (1995) #21, titled “Stalker,” Steel performs a super strength feat. In Washington D.C., still must stop a terrorist attack masterminded by Metallo. During the battle, Steel knocks off Metallo’s head with his hammer.

How much super strength does it take for Steel to knock off Metallo’s head with a kinetic hammer?

In ‘Steel’ (1995) #21, titled “Stalker,” Steel performs a super strength feat. During the battle, Steel knocks off Metallo’s head with his hammer. AP Photo/DC Comics.

STEEL HIT METALLO WITH ABOUT 2668674.17122 NEWTONS OF IMPACT FORCE IN AN ELASTIC COLLISION THAT REMOVED HIS 5.054 KILOGRAM HEAD FROM HIS BODY.

STEEL GENERATED 13343370.8561 JOULES OF KINETIC ENERGY WITH HIS KINETIC HAMMER, 153715.632262 TIMES THE DAILY ENERGY EXPENDITURE OF A HUMAN BEING PER DAY OR CLASS 100+ WITH 8086354.7288 TONS OF SUPER-STRENGTH, ENOUGH TO DESTROY A WALL.

SUPER STRENGTH FEAT:

CITY

                       

For our database entries on DC Power Levels, visit the DC page!

Head over to Evolution of Steel in Cartoons, Movies & TV in 6 Minutes (2019) by ComicBook Debate.

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VISIT OUR CALCULATIONS

Steel is in Washington D.C. and must stop a terrorist attack masterminded by Metallo. Metallo has a new body and Steel uses a strategy used by Superman in his battles against Metallo: He knocks off Metallo’s head. Refer to the calculations in the Show/Hide Toggle.

METALLO’S DURABILITY

Typically, Metallo is made of an indestructible steel alloy. We will use Metallo’s feat in ‘Adventures of Superman’ (1992) #491, in order to calculate Metallo’s durability. Here, Metallo’s indestructible metal alloy upgraded by Cerberus actually reflects Superman’s heat vision.

In 'Adventures of Superman' (1992) #491, Metallo's indestructible metal alloy upgraded by Cerberus actually reflects Superman's heat vision.
In ‘Adventures of Superman’ (1992) #491, Metallo’s indestructible metal alloy upgraded by Cerberus actually reflects Superman’s heat vision. AP Photo/DC Comics.

NUMBER CRUNCHING

Metallo’s upgraded steel alloy reflected Superman’s heat vision. Typically, Superman’s heat vision reaches temperatures as hot as the sun’s surface, which is about 5520 degrees C. Let’s calculate the thermal energy discharged by Superman in order to estimate Metallo’s durability.

Thermal Energy = W on system = (5,520 C-20 C)(480 J/kg C)(272.155 kg*0.2) = 13343370.8561 J.

It takes more than 13343370.8561 Joules of energy in order to destroy Metallo’s upgraded steel alloy. This is merely a rough estimate and it is very possible that it would take millions of degrees Celsius, a temperature matching the sun’s core, in order to melt Metallo’s upgraded steel alloy. Our strategy is to use the Conservation of Energy to calculate the kinetic energy used by Steel’s kinetic hammer to knock off Metallo’s head from the thermal energy or work done on the system.

From 4.4: Momentum And Energy, we find:

Wonsystem=ΔKEsystem⟺FΔx1=1/2m1v12

Since the change in kinetic energy equals the work done on the system, we can calculate the impact force in the elastic collision. The elastic collision caused Metallo’s head to travel five meters from its body. We previously assumed that Metallo’s head was approximately 1.8% of his body weight. This is in relation to the human brain weighing about 1.3 kg.

Let’s calculate Metallo’s Super Strength Level. According to the SUPERPOWERWIKI, Peak Human Strength is between 800-1000 lbs. Let’s use the higher value of 1000 lbs which converts to 453.592 kg. We can use Metallo’s durability ratio in comparison to a human being’s daily energy expenditure in order to calculate Metallo’s Super-Strength.

Metallo’s Super-Strength = Peak Human Strength * (153715.632262)(1/0.01857142857) = 8086354728.8 kg = 8086354.7288 ​Tons

SUPER-STRENGTH

Metallo’s upgraded indestructible steel alloy can reflect Superman’s heat vision. The energy needed to melt Metallo’s steel alloy is likely in the millions of degrees Celsius, which is as hot as the sun’s core. In our calculations, we assumed Steel matched the thermal energy of Superman’s heat vision with his kinetic hammer.

Steel’s kinetic hammer generated 13343370.8561 Joules of kinetic energy knocking off Metallo’s head in an elastic collision. Using an energy ratio, we rated Metallo’s Super-Strength to be 8086354.7288 ​Tons, which is the City Level of Super-Strength.

Toggle the Toggle Arrow below to view the calculations.

Calculations for Steel, ‘Steel’ #21

Specific Heat Capacity Of Steel = 480 J/kg C
Energy Expenditure By A Human In A Day = 7,500,000 J/day.
Mass Of Metallo = 272.155 kg.
Temperature At The Surface Of The Sun = 5520 C.

Thermal Energy = W on system = (5,520 C-20 C)(480 J/kg C)(272.155 kg*0.01857142857) = 13343370.8561 J.
Impact Force = W/d = (113343370.8561 J)/(5 m) = 2668674.17122 N. Ratio = (13343370.8561 J * 24 hr * 3600 * 1 day)/(7,500,000 J/day * 1 hr * 1 s) = 153715.632262.
Metallo’s Super-Strength = Peak Human Strength * (153715.632262)(1/0.01857142857) = (453.592 kg)(331079.82336)(1/0.01857142857) = 8086354728.8 kg = 8086354.7288 Tons.


SOURCES

Steel Vol 2 21 in DC Database.
John Henry Irons (New Earth) in DC Database.
John Corben (New Earth) in DC Database.
4.4: Momentum And Energy in Physics LibreTexts.
Peak Human Listing in SUPERPOWERWIKI.

Feat: Luke Cage, ‘Fantastic Four’ #169

IN POWER LEVEL

LUKE CAGE
EARTH-616

In ‘Fantastic Four’ (1961) #169, titled “Five Characters In Search Of A Madman”, Power Man performs a super strength feat. In an attempt to replace Ben Grimm who has lost his super powers, Power Man is being manipulated by an unknown force into fighting the Fantastic Four. During the fight, Power Man breaks Invisible Woman’s force fields with two punches.

How much super strength does it take for Power Man to break Invisible Girl’s force fields with two punches?

In 'Fantastic Four' (1961) 169, Power Man breaks Invisible Woman's force fields with two punches.
In ‘Fantastic Four’ (1961) #169, Power Man performs a super strength feat. Power Man breaks Invisible Woman’s force fields with two punches. AP Photo/Marvel Comics.

POWER MAN BROKE INVISIBLE GIRL’S FORCE FIELDS WITH TWO PUNCHES OF STRESS 522,019.40845 PSI.

POWER MAN GENERATED THE EQUIVALENT OF HITTING INVISIBLE GIRL’S FORCE FIELD WITH A SLEDGEHAMMER TWICE WITH IMPACT FORCE OF 18,000 PSI, FIVE PERCENT OF THE POWER PRODUCED BY A HOUSE PER HOUR, ENOUGH TO DESTROY AN ATHLETE.

DURABILITY FEAT:

METAHUMAN

           

For our database entries on Marvel Power Levels, visit the Marvel page!

Head over to How Strong is Luke Cage ~ Marvel Comics | how STRONG series by IvaN The UnStoppable.

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VISIT OUR CALCULATIONS

Calculations for Luke Cage, ‘Fantastic Four’ #169

Area = pi(r^2) = (pi)(15^2 cm^2) = 706.858347058 cm^2.
Force Of Sledgehammer = (18000 psi)(6894.76) = 124105680 N.
Stress Of Second Punch = (254648 N)/(cos60) = 267371.40845 N.
Total Stress Of Two Punches =(254648 N + 267371.40845 N) = 522019.40845 N.
https://raahsafety.com/slide-sledge-hammer.html
(522019.40845 J)(1 Ton of TNT)/(4.2*10^9 J) = 0.00012429033 Tons of TNT
Percent Of Energy Produced Per Hour = (522019.40845*100)/(10399000 kWhr) = 5.01990007164%.

Luke Cage, ‘Fantastic Four’ #169

SOURCES

Fantastic Four Vol 1 169 in Marvel Database.

Krypton: In An Attempt To Destroy The Superman Dynasty, Solaris Turns The Sun Red

KRYPTON

In 'All-Star Superman' (2008) #11, Solaris has turned the sun red.
In ‘All-Star Superman’ (2008) #11, Solaris has turned the sun red. AP Photo/DC Comics.

IN MAD SCIENCE

After a trip to the sun saving astronomers, Superman was exposed by Lex Luthor to an overload of solar radiation that has not only tripled his super strength with added super powers, but is causing him to die. With moments left before his death, Superman must complete his twelve labors in order to save the Superman dynasty.

Lex Luthor has stolen the Super Serum formula and has developed Superman’s super powers for 24 hours. In order to defeat his nemesis, once and for all, he has recruited a “secret ally”. Solaris has turned the sun red and intends to destroy the Superman dynasty. This is ‘All-Star Superman.’

Database Comics

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Feat: Hulk, ‘Incredible Hulk’ #54

IN SUPERHERO BATTLES

HULK (BRUCE BANNER)
EARTH-616

In ‘Incredible Hulk’ (2003) #54, titled “Welcome To Entropy,” Hulk performs a super strength feat. In New Mexico, Hulk is manipulated by Home Base and Nadia Donorva. In Entropy, Hulk has to battle Abomination. During the fight, Hulk implodes Abomination’s face with a punch.

How much super strength does it take for Hulk to implode the Abomination’s face with a punch?

In 'Incredible Hulk' (2003) #54, Hulk performs a super strength feat. Hulk implodes Abomination's face with a punch.
In ‘Incredible Hulk’ (2003) #54, Hulk performs a super strength feat. During the fight, Hulk implodes Abomination’s face with a punch.

HULK PUNCHED THE ABOMINATION WITH 13602858368.4 NEWTONS OF FORCE OR 7891709 PSI OF STRESS.

HULK GENERATED THE EQUIVALENT OF 13602858368.4 JOULES OF ENERGY, 1.237 TIMES THE ENERGY PRODUCED BY NEW YORK CITY IN A DAY, ENOUGH TO DESTROY A LARGE BUILDING.

SUPER STRENGTH FEAT:

CITY

         

For our database entries on Marvel Power Levels, visit the Marvel page!

Head over to Hulk vs. Abomination – Epic of Smash by Comics Fighters.

Comics Fighters

VISIT OUR CALCULATIONS

Toggle the Toggle Arrow below to view the calculations.

Calculations for Hulk, ‘Incredible Hulk’ #54

Energy of heat of re-entry (Max durability of Abomination) = (1/2)mv^2 = (0.5)(444.52 kg)(7823.2 m/s) = 13602858368.4 J.
Ratio Energy of re-entry/Energy produced by New York = (13602858368.4 J-hr)/(11000000000 J-hr) = 1.237.
(13602858368.4 J)(1 Ton of TNT)/(4.2*10^9 J) = 3.239 Tons of TNT


Hulk, ‘Incredible Hulk’ #54

SOURCES

Incredible Hulk Vol 2 54 in Marvel Database.
Emil Blonsky (Earth-616) in Marvel Database.