IN POWER LEVEL
In ‘Fantastic Four’ (1961) #169, titled “Five Characters In Search Of A Madman”, Power Man performs a super strength feat. In an attempt to replace Ben Grimm who has lost his super powers, Power Man is being manipulated by an unknown force into fighting the Fantastic Four. During the fight, Power Man breaks Invisible Woman’s force fields with two punches.
How much super strength does it take for Power Man to break Invisible Girl’s force fields with two punches?
POWER MAN BROKE INVISIBLE GIRL’S FORCE FIELDS WITH TWO PUNCHES OF STRESS 522,019.40845 PSI.
POWER MAN GENERATED THE EQUIVALENT OF HITTING INVISIBLE GIRL’S FORCE FIELD WITH A SLEDGEHAMMER TWICE WITH IMPACT FORCE OF 18,000 PSI, FIVE PERCENT OF THE POWER PRODUCED BY A HOUSE PER HOUR, ENOUGH TO DESTROY AN ATHLETE.
For our database entries on Marvel Power Levels, visit the Marvel page!
VISIT OUR CALCULATIONS
Calculations for Luke Cage, ‘Fantastic Four’ #169
Area = pi(r^2) = (pi)(15^2 cm^2) = 706.858347058 cm^2.
Force Of Sledgehammer = (18000 psi)(6894.76) = 124105680 N.
Stress Of Second Punch = (254648 N)/(cos60) = 267371.40845 N.
Total Stress Of Two Punches =(254648 N + 267371.40845 N) = 522019.40845 N.
(522019.40845 J)(1 Ton of TNT)/(4.2*10^9 J) = 0.00012429033 Tons of TNT
Percent Of Energy Produced Per Hour = (522019.40845*100)/(10399000 kWhr) = 5.01990007164%.